mirror of
https://github.com/TerryCavanagh/VVVVVV.git
synced 2026-01-29 17:38:16 +03:00
Explicitly declare void for all void parameter functions (#628)
Apparently in C, if you have `void test();`, it's completely okay to do `test(2);`. The function will take in the argument, but just discard it and throw it away. It's like a trash can, and a rude one at that. If you declare it like `void test(void);`, this is prevented. This is not a problem in C++ - doing `void test();` and `test(2);` is guaranteed to result in a compile error (this also means that right now, at least in all `.cpp` files, nobody is ever calling a void parameter function with arguments and having their arguments be thrown away). However, we may not be using C++ in the future, so I just want to lay down the precedent that if a function takes in no arguments, you must explicitly declare it as such. I would've added `-Wstrict-prototypes`, but it produces an annoying warning message saying it doesn't work in C++ mode if you're compiling in C++ mode. So it can be added later.
This commit is contained in:
@@ -8,10 +8,10 @@
|
||||
class entclass
|
||||
{
|
||||
public:
|
||||
entclass();
|
||||
void clear();
|
||||
entclass(void);
|
||||
void clear(void);
|
||||
|
||||
bool outside();
|
||||
bool outside(void);
|
||||
|
||||
void setenemy(int t);
|
||||
|
||||
@@ -19,9 +19,9 @@ public:
|
||||
|
||||
void settreadmillcolour(int rx, int ry);
|
||||
|
||||
void updatecolour();
|
||||
void updatecolour(void);
|
||||
|
||||
bool ishumanoid();
|
||||
bool ishumanoid(void);
|
||||
|
||||
public:
|
||||
//Fundamentals
|
||||
|
||||
Reference in New Issue
Block a user